Text that Bell Ringer i m sorry of the complying with aqueous options will cause litmus file to revolve red? A NaOH B...




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Bell Ringer which of the following aqueous remedies will cause litmus record to rotate red? A NaOH B NaCl C HCl D H 2 O pH1-678-14 Solution included Litmus record changes native AcidNeutralBase Blue come Red does not adjust Red come Blue Source: 2003 VA EOC test Slide 2 pH Acids and Bases on slide 3 A fast Reminder Reactions have the right to stop at an EQUILIBRIUM picture source: http://cwx.prenhall.com NO 2 + NO 2 N 2 O 4 on slide 4 The Equilibrium Constant, K eq c dc d a ba b because that the reaction: aA + bB cC + dD Where: a, b, c, d are coefficients A, B, C, D room substances (products) (reactants) < > = concentration in M K eq = slide 5 The Equilibrium Constant, K eq for the reaction: NO 2 + NO 2 N 2 O 4 K eq = 1 1 K eq = 1 2 2 NO 2 N 2 O 4 = 2 = 2 on slide 6 A special Equilibrium Constant, K w for the reaction: H 2 O + H 2 O H 3 O + + five - K w = 2 = K w = <1.00 x 10 -7 > = 1.00 x 10 -14 hydroniumhydroxide photo source: http://cwx.prenhall.com slide 7 Practice difficulties Using the knowledge that K w = 1.00 x 10 -14, fix for the absent piece of information: 1. Calculation the hydroxide ion concentration in a solution whose hydronium ion concentration is 1 x 10 -5 M K w = 1.00 x 10 -14 = <1 x 10 -5 M> = 1.00 x 10 -14 1 x 10 -5 M = 1 x 10 -9 M slide 8 Practice troubles 2. Calculate the hydronium concentration for a systems whose hydroxide concentration is 0.0010 M. K w = 1.00 x 10 -14 = <0.0010 M> = 1.00 x 10 -14 0.0010 M = 1 x 10 -11 M slide 9 Practice troubles 3. What is the hydroxide concentration the a equipment if 0.080 grams the NaOH are liquified in 2.0 together of solution? What is the hydronium ion concentration that this solution? 0.080 g NaOH x 1 mol NaOH 40.00 g NaOH x 1 mol five - 1 mol NaOH = 0.0020 mol oh - =0.0020 mol five - 2.0 together =0.0010 M oh - K w = 1.00 x 10 -14 = <0.0010 M> = 1.00 x 10 -14 0.0010 M =1.0 x 10 -11 M H 3 O + on slide 10 Practice troubles 4. What is the hydroxide ion concentration of a equipment if 0.080 grams that Ca(OH) 2 are dissolved in 2.0 l of solution? What is the hydronium ion concentration that this solution? 0.080 g Ca(OH) 2 x 1 mol Ca(OH) 2 74.10 g Ca(OH) 2 x 2 mol oh - 1 mol Ca(OH) 2 = 0.00216 mol oh - =0.00216 mol five - 2.0 together =0.00108 M five - K w = 1.00 x 10 -14 = <0.00108 M> = 1.00 x 10 -14 0.00108 M =9.3 x 10 -12 M H 3 O + 0.0020 M five - 9.3 x 10 -12 M H 3 O + on slide 11 pH the power of H + ! these numbers stand for the power of H + pH = the an unfavorable logarithm the image source: http://www.lowimpactdevelopment.org slide 12 Log-o-rhythms == pH = the an unfavorable logarithm the POWER pH the power of H + ! price the adhering to questions without utilizing a calculator: What is the pH the a solution with = 1.0 x 10 -4 M? pH = 4.00ACID What is the pH the a solution with = 1.0 x 10 -12 M? pH = 12.00BASE pH = - log in on slide 13 my Kingdom because that a Calculator! on TI-83: press (-) vital push log in key form in number On clinical Calculators: form in number push log key push +/- crucial To deal with for pH, provided hydronium molarity slide 14 Practice troubles 1. What is the pH of a systems if the concentration that hydronium ion is 1.0 x 10 -2 M? Is the systems acidic or basic? pH = - log pH = - log in (1.0 x 10 -2 ) pH = 2.00ACIDIC SIG FIG RULES: put the correct variety of Sig Figs BEHIND the decimal point. On slide 15 Practice difficulties 2. What is the pH that a solution if the concentration the hydroxide ion is 1.0 x 10 -4 M? Is the equipment acidic or basic? pH = - log in pH = - log in (1.0 x 10 -10 ) pH = 10.00BASIC K w = 1.00 x 10 -14 = <1.0 x 10 -4 M> = 1.00 x 10 -14 1.0 x 10 -4 M = 1 x 10 -10 M slide 16 my Kingdom because that a Calculator (again)! ~ above TI-83: press 10 x an essential push (-) key form in pH On scientific Calculators: form in number push +/- vital push 2 nd vital push log key To fix for hydronium molarity, provided pH on slide 17 Practice troubles 3. What is the concentration the hydronium ions in a equipment whose pH is 8.00? pH = 8.00 = - log -8.00 = log in 10 8.00 M = = 1.00 x 10 -8 M slide 18 Practice troubles 4. For question #3, what is the concentration of hydroxide ions? K w = 1.00 x 10 -14 = <1.0 x 10 -8 M> = 1.00 x 10 -14 1.0 x 10 -8 M = 1 x 10 -6 M on slide 19 Practice troubles 5. What is the concentration of hydronium ions in a equipment that has a volume the 2.50 L and also 5.33 g that HCl? What is the pH the this solution? 5.33 g HCl x 1 mol HCl 36.46 g HCl x 1 mol H + 1 mol HCl = 0.146 mol H + =0.146 mol H + 2.50 together =0.0584 M H + pH = - log in pH = - log in (0.0584) pH = 1.234 on slide 20 Homework complete the practice troubles on the worksheet. early next course


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