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This is university Physics Answers through Shaun Dychko We begin by creating down the info the question gives us, the tells united state that the freight train speeds up at a rate of .05 meters per second squared. And also it"s walk to do so because that a period of 8 minutes, which us will convert into seconds since we constantly want to have actually MKS systems in our job-related here. We desire meters, kilograms and also seconds. And also so, below we have actually minutes and also we rather want seconds. So, we convert it to secs by multiplying by 60 secs per minute. That offers 480 seconds. And also the early stage velocity that this freight train is 4.0 meters every second. And so, what will certainly the last velocity be after the 8 minutes? Well, it"s walking to be the initial velocity plus acceleration multiplied by time. So, that"s 4.00 meter per 2nd plus 0.0500 meters per 2nd squared times 480 seconds, offering us 28.0 meters per second as the last velocity. Now, if the freight train pertains to a avoid from this velocity right here of 28 meters second, through an acceleration of an unfavorable .550 meters per second squared, just how long will that take? So, our meaning of acceleration is the it"s the difference in velocities separated by time. And we"ll multiply both sides by t here since we desire it to it is in in the numerator. We don"t want it in the denominator. "t " is the variable we room trying to settle for. And, that renders it disappear in the right, and then, it shows up top top the left multiplied by a. And then, we division both political parties by the acceleration giving us t equals final velocity minus early stage velocity divided by acceleration. So, that"s 0 final velocity, since it comes to a stop, minus the initial velocity that 28.0 meters per 2nd that us calculated in component A, and also divide that by negative .55 meter per 2nd squared, providing us 50.9 secs for the train come stop. And, currently in part C, we"re going to discover the street traveled in each of these scenarios of part A and B. So, in component A, we recognize that the final position will certainly be the initial place plus the early velocity time time plus one-half times acceleration times time squared. And so, the 0 add to 4.0 meters per second times 480 seconds plus one-half times .05 meter per second squared times 480 seconds entirety squared. And also that provides 7680 meters the the train travels when it"s comes to a stop. So, you can see that the train takes a long time to stop due to the fact that it takes... Or sorry. Actually, we"re not avoiding here, space we? No, no, no. Never mind, sorry. We"re speeding up here. This is component A. Yeah. So, the train takes practically 8 kilometers to obtain up to speed. The freight train accelerates very slowly. Now, for part B, We"re walk to usage a different formula due to the fact that it"s... It"s always best practice to usage as little calculated info in your work as possible. So, we can use this formula if we wanted to due to the fact that we know how long it takes because that the train come stop. The takes 50.9 seconds and also we recognize the velocity the it starts v of 28.0 meters per second, yet that"s two quantities that we calculated and it"s feasible that we made a mistake in among them. And also we wouldn"t desire that mistake to then do our answer because that this calculation wrong together well. So, we pick a formula the reduces the amount of ingredient that we calculated in it. And also so, we"ll use this formula here, which go not usage this time. It still offers the final velocity that us calculated in component A. So, we can"t stop this problem entirely, but, in ~ least, we"re using only one calculate number rather of two of them. So, we have final velocity together initial velocity plus two times acceleration multiplied by the displacement - last position minus initial position. So, we want to settle for this bracket below - this x minus x naught and we will carry out that by individually v nothing squared indigenous both sides and also then switch the sides around. And it will certainly disappear here, leave 2a time displacement equals distinction of velocity... The squares of the velocities. And also then, divide both political parties by 2a. The cancels there, leaving us with displacement is the difference in the squares the the velocities separated by 2 times acceleration. So, it concerns a stop. That method that final velocity is zero and also then minus 28.0 meter per second squared split by 2 times an unfavorable .550 meter per 2nd squared. And then, that provides us 713 meters end which the train travel while the is stopping. So, that goes quite much when the stops and that"s because it"s therefore heavy.
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Time 2:02 girlfriend are splitting by the acceleration that is 0.0500 together per the text, however the number in the video is 0.500 throwing the results off. I get 560 secs.
Ah, for component B the this question, and for "part B the C", the acceleration offered by the problem is different than it is for component A. The acceleration in these components is no 0.0500, but rather -0.550.